Q.7 An elevator descends into a nine shaft at the rate of 6 m/min. If the descent starts from 10 m above the ground level, how long will it take to reach -350 m.


Answer :

The present position of the elevator is at 10 in above the ground level.
Distance moved by the elevator below the ground level = 350 m
Therefore Total distance moved by the elevator = 350 m + 10 m = 360 m
Rate of descent = 6 m/min.
Total time taken by the elevator
=360m ÷ 6m/min = 60 minutes = 1 hour
Hence, the required time = 1 hour.

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