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# Q.1 Solve i) $$2 - \frac{3}{5}$$ ii) $$4 + \frac{7}{8}$$ iii) $$\frac{3}{5}+\frac{2}{7}$$ iv) $$\frac{9}{11}-\frac{4}{15}$$ v) $$\frac{7}{10}+\frac{2}{5}+\frac{3}{2}$$ vi) $$2\frac{2}{3}+3\frac{1}{2}$$ vii) $$8\frac{1}{2}-3\frac{5}{8}$$

(i) $$2- \frac{3}{5} = \frac{2×5-3}{5}= \frac{7}{5} = 1\frac{2}{5}$$
ii) $$4 + \frac{7}{8} = \frac{8×4+7}{8}= \frac{39}{8}=4\frac{7}{8}$$
iii) $$\frac{3}{5}+\frac{2}{7} = \frac{7×3+5×2}{35}=\frac{21+10}{35}= \frac{31}{35}$$
iv) $$\frac{9}{11}-\frac{4}{15}= \frac{15×9-11×4}{165}= \frac{135-44}{165}= \frac{91}{165}$$
v) $$\frac{7}{10}+ \frac{2}{5}+\frac{3}{2} = \frac{7×1+2×2+3×5}{10}= \frac{7+4+15}{10} =\frac{26}{10} =\frac{26÷2}{10÷2} =\frac{13}{5} =2\frac{3}{5}$$
vi) $$2\frac{2}{3}+3\frac{1}{2} = \frac{8}{3}+\frac{7}{2}= \frac{2×8+3×7}{6}= \frac{16+21}{6}=\frac{37}{6}= 6\frac{1}{6}$$
vii) $$8\frac{1}{2}-3\frac{5}{8} = \frac{17}{2}-\frac{29}{8}= \frac{17×4-29×1}{8}= \frac{68-29}{8} = \frac{39}{8} =4\frac{7}{8}$$