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# How many multiples of 4 lie between 10 and 250?

First multiple of 4 which lie between 10 and 250 is 12.

The last multiple of 4 which lie between 10 and 250 is 248.

Therefore, AP is of the form 12, 16, 20… ,248

First term = a = 12,
Common difference = d = 4

Using formula $$a_n$$ = a + (n – 1) d, to find $$n^{th}$$ term of arithmetic progression,

$$\Rightarrow$$ 248 = 12 + (n - 1) (4)
$$\Rightarrow$$ 248 = 12 + 4n - 4
$$\Rightarrow$$ 240 = 4n
$$\Rightarrow$$ n = 60

It means that 248 is the $$60^{th}$$ term of AP.

So, we can say that there are 60 multiples of 4 which lie between 10 and 250.