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(i) 2.5 ×0.3

(ii) 0.1 × 51.7

(iii) 0.2 × 316.8

(iv) 1.3 × 3.1

(v) 0.5 × 0.05

(vi) 11.2 × 0.15

(vii) 1.07 × 0.02

(viii) 10.05 × 1.05

(ix) 100.01 × 1.1

(x) 100.01 × 1.1

Answer :

(i) 0 2.5 × 0.3

\(\therefore \)25 × 3 = 75 and there are 2 digits (1 + 1) right to the decimal points in 2.5 and 0.3.

Thus 2.5 × 0.3 = 0.75

(ii) 0.1 × 51.7

\(\therefore \) 1 × 517 = 517 and there are two digits (1 + 1) right to the decimal places in 0.1 and 51.7.

(iii) 0.2 × 316.8

\(\therefore \) 2 × 3168 = 6336 and there are 2 digits (1 + 1) right to the decimal points in 0.2 and 316.8.

Thus 0.2 × 316.8 = 63.36.

(iv) 1.3 × 3.1

\(\therefore \) 13 × 31 = 403 and there are 2 digits (1 + 1) right to the decimal points in 1.3 and 3.1.

Thus 1.3 × 3.1 – 4.03

(v) 0.5 × 0.05

\(\therefore \) 5 × 5 = 25 and there are 3 digits (1 + 2) right to the decimal points in 0.5 and 0.05.

Thus 0.5 × 0.05 = 0.025

(vi) 11.2 × 0.15

\(\therefore \) 112 × 15 = 1680 and there are 3 digits (1 + 2) right to the decimal points in 11.2 and 0.15.

Thus 11.2 × 0.15 = 1.680

(vii) 1.07 × 0.02

\(\therefore \) 107 × 2 = 214 and there are 4-digits (2 + 2) right to the decimal places is 1.07 × 0.02.

Thus 1.07 × 0.02 = 0.0214

(viii) 10.05 × 1.05

\(\therefore \) 1005 × 105 = 105525 and there are 4 digits (2 + 2) right to the decimal places in 10.05 × 1.05.

Thus 10.05 × 1.05 = 10.5525

(ix) 101.01 × 0.01

\(\therefore \) 10101 × 1 = 10101 and there are 4 digits (2 + 2) right to the decimal places in 101.01 and 0.01.

Thus 101.01 × 0.01 = 1.0101

(x) 100.01 × 1.1

\(\therefore \) 10001 × 11 = 110011 and there are 3 digits (2 + 1) right to the decimal points in 100.01 and 1.1.

Thus 100.01 × 1.1 = 110.011.

- Q.1 Find: (i) 0.2 × 6 (ii) 8 × 4.6 (iii) 2.71 × 5 (iv) 20.1 × 4 (v) 0.05 × 7 (vi) 211.02 × 4 (vii) 2 × 0.86
- Q.2 Find the area of rectangle whose length is 5.7 cm and breadth is 3 cm.
- Q.3 Find: (i) 1.3 × 10 (ii) 36.8 × 10 (iii) 153.7 × 10 (iv) 168.07 × 10 (v) 31.1 × 100 (vi) 156.1 × 100 (vii) 3.62 × 100 (viii) 43.07 × 100 (ix) 0.5 × 10 (x) 0.08 × 10 (xi) 0.9 × 100 (xii) 0.03 × 1000
- Q.4 A two-wheeler covers a distance of 55.3 km in one litre of petrol. How much distance will it cover is 10 litres of petrol?

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