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Answer :
(i) Number of points scored by A in all games are
Game 1 = 14, Game 2 = 16, Game 3 = 10, Game 4 = 10
Therefore Average score \(=\frac{14+16+10+10}{4}=\frac{50}{4}=12.5 \)
(ii) Since, C did not play Game 3, he played only 3 games. So, the total will be divided by 3.
(iii) Number of points scored by B in all the games are Game 1 = 0, Game 2 = 8, Game 3 = 6, Game 4 = 4
Therefore Average score \(=\frac{0+8+6+4}{4}=\frac{18}{4}= 4.5 \)
(iv) Mean score of C \(=\frac{8+11+14}{3}=\frac{32}{3}=10.67
Mean score of C = 10.67
While mean score of A = 12.5
Clearly, A is the best performer.