Q.2 Check whether the value given in the brackets is a solution to the given equation or not:
(a) n + 5 = 19; (n = 1)
(b) 7n + 5 = 19; in – -2)
(c) 7n + 5 = 19; (n = 2)
(d) 4p – 3 = 13; (p = 1)
(e) 4p – 3 = 13; (p = -4)
(f) 4p-3 = 13; (p = 0)


Answer :

(a) n + 5 = 19 (n = 1) Put n = 1 in LHS
1 + 5 = 6
RHS =19
Since LHS ? RHS
Thus n = 1 is not the solution of the given equation. "n+5=19"
(b) 7n + 5 = 19 (n = -2) Put n = -2 in LHS
-2×7 + 5 = -9
RHS =19
Since LHS \(\neq \)RHS
Thus n = -2 is not the solution of the given equation. "7n+5=19"
(c) 7n + 5 = 19 (n = 2) Put n = 2 in LHS
7×2 + 5 = 19
RHS =19
Since LHS = RHS
Thus n = 2 is the solution of the given equation. "7n+5=19"
(d) 4p-3 = 13 (p= 1) Put p = 1 in LHS
4×1-3 = 1
RHS =13
Since LHS \(\neq \)RHS
Thus p = 1 is not the solution of the given equation. "4p-3=13"
(e) 4p - 3= 13 (p = -4) Put p = -4 in LHS
4×(-4) - 3 = -19
RHS =13
Since LHS \(\neq \)RHS
Thus p = -4 is not the solution of the given equation. "4p-3=13"
(f) 4p-3=13 (p= 0) Put p = 0 in LHS
0×4-3 = -3
RHS =13
Since LHS \(\neq \) RHS
Thus p = 0 is not the solution of the given equation. "4p-3=13"

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