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Q.1 Solve the following equations:
(a) 2y + (5/2) = (37/2)
(b) 5t + 28 = 10
(c) (a/5) + 3 = 2
(d) (q/4) + 7 = 5
(e) (5/2) x = -5
(f) (5/2) x = 25/4
(g) 7m + (19/2) = 13
(h) 6z + 10 = – 2
(i) (3/2) l = 2/3
(j) (2b/3) – 5 = 3

Answer :

(a) 2y + (5/2) = (37/2)
= 2y = (37/2) – (5/2)
= 2y = (37-5)/2
= 2y = 32/2
= y = 16/2 = 8
(b) 5t+28= 10
= 5t = 10 -28
= t= -18/5
(c) a/5+3 =2
= a/5= 2-3
= a=-1×5=-5
(d) q/4+7 = 5
= q/4=5-7
=a= -2 ×4= -8
(e) (5/2)x = -5
= 5x=-5×2
= x= -10/5=-2
(f) 5x/2=25
= 5x = 25×2
= x = 50/5 =10
(g) 7m+19/2 =13
= 7m = 13 -19/2 = 7m = (26-19)/2
= 7m= 7/2
= m = 7/2×1/7 =1/2
(h) 6z + 10 = -2
= 6z = -2 -10
= z = -12/ 6 = -2
(i) (3/2)I = 2/3
= I = 2/3 × 2/3 =4/9
(j) (2b/3 ) - 5 = 3
= 2b/3 = 3+5
= 2b/3 = 8
= b = (8×3)/2 = 12