Given
AB \(\parallel \) DE
BC \(\parallel \) EF
\(\angle \)ABC = 70°
\(\angle \)DGC = \(\angle \)ABC
(i) \(\angle \)DGC = 70° (Pair of corresponding angles)
\(\angle \)DEF = \(\angle \)DGC
(ii) \(\angle \)DEF = 70° (Pair of corresponding angles)