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Q.1 PQR is a triangle, right-angled at P. If PQ = 10 cm and PR = 24 cm, find QR.
Answer :
In right angled triangle PQR, we have
\(QR^2 = PQ^2 + PR^2 \) [From Pythagoras property]
\(QR^2 = 10^2 + 24^2 \)
\(QR^2 = 100 + 576 = 676 \)
\(\therefore QR = \sqrt{676} = 26 cm \)
The, the required length of QR = 26 cm.