Q.1 PQR is a triangle, right-angled at P. If PQ = 10 cm and PR = 24 cm, find QR.

$$QR^2 = PQ^2 + PR^2$$ [From Pythagoras property]
$$QR^2 = 10^2 + 24^2$$
$$QR^2 = 100 + 576 = 676$$
$$\therefore QR = \sqrt{676} = 26 cm$$ The, the required length of QR = 26 cm.