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# Q.2 ABC is a triangle, right angled at C. If AB = 25 cm and AC = 7 cm, find BC.

In right angled?ABC, we have
$$BC^2 + 7^2 = 25^2$$(By Pythagoras property)
Or, $$BC^2 + 49 = 625$$
Or, $$BC^2 = 625 – 49$$
Or, $$BC^2 = 576$$
$$\therefore BC = \sqrt{576} = 24 cm$$
Thus, the required length of BC = 24 cm.