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Answer :

Here, the ladder forms a right angled triangle.

\(\therefore \) \(a^2 + 12^2 = 15^2 \)(By Pythagoras property)

Or, \(a^2+ 144 = 225\)

Or, \(a^2 = 225 – 144 \)

Or, \(a^2 = 81 \)

\(\therefore \) a = \(\sqrt{81}= 9 \) m

Thus, the distance of the foot from the ladder = 9m

- Q.1 PQR is a triangle, right-angled at P. If PQ = 10 cm and PR = 24 cm, find QR.
- Q.2 ABC is a triangle, right angled at C. If AB = 25 cm and AC = 7 cm, find BC.
- Q.4 Which of the following can be the sides of a right triangle? (i) 2.5 cm, 6.5 cm, 6 cm. (ii) 2 cm, 2 cm, 5 cm. (iii) 1.5 cm, 2 cm, 2.5 cm
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- Q.6 Angles Q and R of a APQR are 25° and 65°. Write which of the following is true. (i) \( PQ^2 + QR^2 = RP^2 \) (ii)\( PQ^2 + RP^2 = QR^2 \) (iii)\( RP^2 + QR^2 = PQ^2 \)
- Q.7 Find the perimeter of the rectangle whose length is 40 cm and a diagonal is 41 cm.
- Q.8 The diagonals of a rhombus measure 16 cm and 30 cm. Find its perimeter.

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