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Q.6 Complete the congruence statement:
\(\triangle BCA \cong ?
\triangle QRS \cong ? \)
Answer :
(i) In \(\triangle BCA and \triangle BTA \)
BC = BT (Given)
\(\angle CBA= \angle TBA (Given) \)
BA= BA (Common)
\(\therefore \triangle BCA = \triangle BTA \) (by SAS rule)
(ii) In \(\triangle QRS and \triangle TPQ \)
RS = PQ (Given)
QS =TQ (Given)
PT= QR (Given)
\(\triangle QRS \cong \triangle TPQ \) (by AAA rule)