Q.3 Give four rational numbers equivalent to:
(i) -2/7
(ii) 5/-3
(iii) 4/9


Answer :

(i) \( \frac{-2}{7} \) = \( \frac{-2×2}{7×2} \) =\( \frac{-4}{14} \)
\( \frac{-2}{7} \) =\( \frac{-2×3}{7×3} \) = \( \frac{-6}{21} \)
\( \frac{-2}{7} \) =\( \frac{-2×4}{7×4} \) = \( \frac{-8}{28} \)
\( \frac{-2}{7} \) =\( \frac{-2×5}{7×5} \) = \( \frac{-10}{35} \)
(ii) \( \frac{5}{-3} \) = \( \frac{5×2}{-3×2} \) =\( \frac{10}{-6} \)
\( \frac{5}{-3} \) =\( \frac{5×3}{-3×3} \) = \( \frac{15}{-9} \)
\( \frac{5}{-3} \) =\( \frac{5×4}{-3×4} \) = \( \frac{20}{-12} \)
\( \frac{5}{-3} \) =\( \frac{5×5}{-3×5} \) = \( \frac{25}{-15} \)
(iii) \( \frac{4}{9} \) = \( \frac{4×2}{9×2} \) =\( \frac{8}{18} \)
\( \frac{4}{9} \) =\( \frac{4×3}{9×3} \) = \( \frac{12}{27} \)
\( \frac{4}{9} \) =\( \frac{4×4}{9×4} \) = \( \frac{16}{36} \)
\( \frac{4}{9} \) =\( \frac{4×5}{9×5} \) = \( \frac{20}{45} \)

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