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# Q.3 Give four rational numbers equivalent to: (i) -2/7 (ii) 5/-3 (iii) 4/9

(i) $$\frac{-2}{7}$$ = $$\frac{-2×2}{7×2}$$ =$$\frac{-4}{14}$$
$$\frac{-2}{7}$$ =$$\frac{-2×3}{7×3}$$ = $$\frac{-6}{21}$$
$$\frac{-2}{7}$$ =$$\frac{-2×4}{7×4}$$ = $$\frac{-8}{28}$$
$$\frac{-2}{7}$$ =$$\frac{-2×5}{7×5}$$ = $$\frac{-10}{35}$$
(ii) $$\frac{5}{-3}$$ = $$\frac{5×2}{-3×2}$$ =$$\frac{10}{-6}$$
$$\frac{5}{-3}$$ =$$\frac{5×3}{-3×3}$$ = $$\frac{15}{-9}$$
$$\frac{5}{-3}$$ =$$\frac{5×4}{-3×4}$$ = $$\frac{20}{-12}$$
$$\frac{5}{-3}$$ =$$\frac{5×5}{-3×5}$$ = $$\frac{25}{-15}$$
(iii) $$\frac{4}{9}$$ = $$\frac{4×2}{9×2}$$ =$$\frac{8}{18}$$
$$\frac{4}{9}$$ =$$\frac{4×3}{9×3}$$ = $$\frac{12}{27}$$
$$\frac{4}{9}$$ =$$\frac{4×4}{9×4}$$ = $$\frac{16}{36}$$
$$\frac{4}{9}$$ =$$\frac{4×5}{9×5}$$ = $$\frac{20}{45}$$