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# Q.9 Which is greater in each of the following: (i) $$\frac{2}{3}$$ , $$\frac{5}{2}$$ (ii) $$\frac{-5}{6}$$ , $$\frac{-4}{3}$$ (iii) $$\frac{-3}{4}$$ , $$\frac{2}{-3}$$ (iv) $$\frac{-1}{4}$$ , $$\frac{1}{4}$$ (v) $$-3\frac{2}{7}$$ , $$-3\frac{4}{5}$$

Answer :

(i) $$\frac{2}{3}$$ = $$\frac{2×2}{3×2}$$=$$\frac{4}{6}$$
$$\frac{5}{2}$$ = $$\frac{5×3}{2×3}$$ = $$\frac{15}{6}$$
Since, $$\frac{2}{3}$$ < $$\frac{5}{2}$$
(ii) $$\frac{-5}{6}$$ = $$\frac{-5×1}{6×1}$$=$$\frac{-5}{6}$$
$$\frac{-4}{3}$$ = $$\frac{-4×2}{3×2}$$ = $$\frac{-8}{6}$$
Since, $$\frac{-5}{6}$$ > $$\frac{-4}{3}$$
(iii) $$\frac{-3}{4}$$ = $$\frac{-3×3}{4×3}$$=$$\frac{-9}{12}$$
$$\frac{2}{-3}$$ = $$\frac{2×4}{-3×4}$$ = $$\frac{8}{-12}$$
Since, $$\frac{-3}{4}$$ < $$\frac{2}{-3}$$
(iv) $$\frac{-1}{4}$$ < $$\frac{1}{4}$$
(v) $$-3\frac{2}{7}$$ = $$\frac{-23}{7}$$ = $$\frac{-23×5}{7×5}$$ = $$\frac{-115}{35}$$
$$-3\frac{4}{5}$$ = $$\frac{-19}{5}$$ =$$\frac{-19×7}{5×7}$$= $$\frac{-133}{35}$$
Since, $$-3\frac{2}{7}$$ > $$-3\frac{4}{5}$$