Q.9 Which is greater in each of the following:
(i) \(\frac{2}{3} \) , \(\frac{5}{2} \)
(ii) \(\frac{-5}{6} \) , \(\frac{-4}{3} \)
(iii) \(\frac{-3}{4} \) , \(\frac{2}{-3} \)
(iv) \(\frac{-1}{4} \) , \(\frac{1}{4} \)
(v) \(-3\frac{2}{7} \) , \(-3\frac{4}{5} \)

(i) \(\frac{2}{3} \) = \(\frac{2×2}{3×2} \)=\(\frac{4}{6} \)
\(\frac{5}{2} \) = \(\frac{5×3}{2×3} \) = \(\frac{15}{6} \)
Since, \(\frac{2}{3} \) < \(\frac{5}{2} \)
(ii) \(\frac{-5}{6} \) = \(\frac{-5×1}{6×1} \)=\(\frac{-5}{6} \)
\(\frac{-4}{3} \) = \(\frac{-4×2}{3×2} \) = \(\frac{-8}{6} \)
Since, \(\frac{-5}{6} \) > \(\frac{-4}{3} \)
(iii) \(\frac{-3}{4} \) = \(\frac{-3×3}{4×3} \)=\(\frac{-9}{12} \)
\(\frac{2}{-3} \) = \(\frac{2×4}{-3×4} \) = \(\frac{8}{-12} \)
Since, \(\frac{-3}{4} \) < \(\frac{2}{-3} \)
(iv) \(\frac{-1}{4} \) < \(\frac{1}{4} \)
(v) \(-3\frac{2}{7} \) = \(\frac{-23}{7} \) = \(\frac{-23×5}{7×5} \) = \(\frac{-115}{35} \)
\(-3\frac{4}{5} \) = \(\frac{-19}{5} \) =\(\frac{-19×7}{5×7} \)= \(\frac{-133}{35} \)
Since, \(-3\frac{2}{7} \) > \(-3\frac{4}{5} \)