Q.2 Find :
(i) \(\frac{7}{24} \) - \(\frac{17}{36} \)
(ii) \(\frac{5}{63} \) - \((-\frac{6}{21}) \)
(iii) \(\frac{-6}{13} \) - \((-\frac{7}{15}) \)
(iv) \(\frac{-3}{8} \) - \(\frac{7}{11} \)
(v) \(-2\frac{1}{9} \) - 6

(i) \(\frac{7}{24} \) - \(\frac{17}{36} \) = \(\frac{7×3}{24×3} \) - \(\frac{17×2}{36×2} \) =\(\frac{21}{72} \) - \(\frac{34}{72} \) = \(\frac{21-34}{72} \) =\(\frac{-13}{72} \)
(ii) \(\frac{5}{63} \) + \(\frac{6}{21} \) = \(\frac{5}{63} \) + \(\frac{6×3}{21×3} \)= \(\frac{5+18}{63} \)= \(\frac{23}{63} \)
(iii) \(\frac{-6}{13} \) - \((-\frac{7}{15}) \)= \(\frac{-6}{13} \) + \(\frac{7}{15} \)
= \(\frac{-6×15}{13×15} \) + \(\frac{7×13}{15×13} \) = \(\frac{-90}{195} \) + \(\frac{91}{195} \) = \(\frac{-90+ 91}{195} \) = \(\frac{1}{195} \)
(iv) \(\frac{-3}{8} \) - \(\frac{7}{11} \) = \(\frac{-3×11}{8×11} \) - \(\frac{7×8}{11×8} \)
=\(\frac{-33}{88} \) - \(\frac{56}{88} \)= \(\frac{-33-56}{88} \) =\(\frac{-89}{88} \)= \(-1\frac{1}{88} \)
(v) \(\frac{-19}{9} \) - 6 = \(\frac{-19-54}{9} \) = \(\frac{-73}{9} \) = \(-8\frac{1}{9} \)