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# Q.2 Find : (i) $$\frac{7}{24}$$ - $$\frac{17}{36}$$ (ii) $$\frac{5}{63}$$ - $$(-\frac{6}{21})$$ (iii) $$\frac{-6}{13}$$ - $$(-\frac{7}{15})$$ (iv) $$\frac{-3}{8}$$ - $$\frac{7}{11}$$ (v) $$-2\frac{1}{9}$$ - 6

(i) $$\frac{7}{24}$$ - $$\frac{17}{36}$$ = $$\frac{7×3}{24×3}$$ - $$\frac{17×2}{36×2}$$ =$$\frac{21}{72}$$ - $$\frac{34}{72}$$ = $$\frac{21-34}{72}$$ =$$\frac{-13}{72}$$
(ii) $$\frac{5}{63}$$ + $$\frac{6}{21}$$ = $$\frac{5}{63}$$ + $$\frac{6×3}{21×3}$$= $$\frac{5+18}{63}$$= $$\frac{23}{63}$$
(iii) $$\frac{-6}{13}$$ - $$(-\frac{7}{15})$$= $$\frac{-6}{13}$$ + $$\frac{7}{15}$$
= $$\frac{-6×15}{13×15}$$ + $$\frac{7×13}{15×13}$$ = $$\frac{-90}{195}$$ + $$\frac{91}{195}$$ = $$\frac{-90+ 91}{195}$$ = $$\frac{1}{195}$$
(iv) $$\frac{-3}{8}$$ - $$\frac{7}{11}$$ = $$\frac{-3×11}{8×11}$$ - $$\frac{7×8}{11×8}$$
=$$\frac{-33}{88}$$ - $$\frac{56}{88}$$= $$\frac{-33-56}{88}$$ =$$\frac{-89}{88}$$= $$-1\frac{1}{88}$$
(v) $$\frac{-19}{9}$$ - 6 = $$\frac{-19-54}{9}$$ = $$\frac{-73}{9}$$ = $$-8\frac{1}{9}$$