Q.1 Construct \(\triangle \)DEF such that DE = 5 cm, DF = 3 cm and \(\angle \) EDF = 90°.


Answer :

1. Draw a line segment DE = 5 cm
2. Draw an angle \(\angle \) EDF = 90 °
3. Cut an arc from D on DF of 3 cm
Then, \(\triangle \) EDF is the required right angled triangle.

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