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Answer :

1. Draw a line segment AB = 5.8 cm.

2. At point A, draw an angle 60° i.e. \(\angle \) A = 60°.

3. At point B, draw an angle of 30° i.e. \(\angle \)B= 30°.

4. Now the two rays intersect at the point C.

Then, \(\triangle \) ABC is the required triangle.

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