Q.2 Construct $$\triangle$$PQR if PQ = 5 cm, m?PQR = 105° and $$\angle$$QRP = 40°.
(Hint: Recall angle-sum property of a triangle)
Given: $$\angle PQR = 40°, \angle QRP = 105°$$
$$\therefore \angle PQR + \angle QRP + \angle QPR = 180°$$ (Angle sum property of a triangle)
105° + 40° +$$\angle$$QPR = 180°
145° + $$\angle$$QPR = 180°
$$\therefore \angle QPR = 180° – 145° = 35°$$
Step 2. At point P, draw an angle $$\angle$$ P = 35°
Step 3 At point Q draw an angle $$\angle$$ Q = 105°
Then, $$\triangle$$PQR is the required triangle.