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Q.7 $$\triangle$$ ABC is right angled at A. AD is perpendicular to BC. If AB = 5 cm, BC = 13 cm and AC = 12 cm, find the area of$$\triangle$$ABC. Also find the length of AD.

Area of triangle = $$\frac{1}{2}$$ × base ×height
$$\therefore$$ $$\frac{1}{2}$$ ×AB×AC = $$\frac{1}{2}$$×BC×AD
Or, $$\frac{1}{2}$$× 5 ×12 = $$\frac{1}{2}$$×13×AD
Or, AD = $$\frac{60}{13}$$ = 4.62 cm