Q.8 $$\triangle$$ABC is isosceles with AB = AC = 7.5 cm and BC = 9 cm. The height AD from A to BC, is 6 cm. Find the area of ?ABC. What will be the height from C to AB i.e., CE?

Area of $$\triangle$$ABC = $$\frac{1}{2}$$ × base × height
$$\therefore$$ $$\frac{1}{2}$$×AB×CE= $$\frac{1}{2}$$×BC×AD
Or, $$\frac{1}{2}$$× 7.5× CE = $$\frac{1}{2}$$× 9×6
Or, CE= $$\frac{54}{7.5}$$= 7.2 cm