Q.5 From a circular sheet of radius 4 cm, a circle of radius 3 cm is removed. Find the area of the remaining sheet. (Take $$\pi$$= 3.14)
Area of the remaining sheet = area of ring = $$\pi (R^2-r^2)$$
$$= 3.14 (4^2-3^2) = 3.14 × (16-9) = 3.14× 7 = 21.98 cm^2$$
Hence, the required area = 21.98 $$cm^2.$$