Q.8 Find the cost of polishing a circular table-top of diameter 1.6 m, if the rate of polishing is Rs.15$$m^2. (Take \pi = 3.14)$$
$$\therefore Radius = \frac{1.6}{2} = 0.8 m$$
Area of the table-top =$$\pi r^2$$
= 3.14 × 0.8 × 0.8 $$m^2$$
= 2.0096 $$m^2$$
$$\therefore$$ Cost of polishing = Rs. 15 × 2.0096