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Answer :
Length of the wire to be bent into a circle = 44 cm
2\(\pi \)r = 44 cm
Or, 2 ×\(\frac{22}{7} \) × r = 44 cm
Or, r = \(\frac{44×7}{22×2} \)
Area of circle \(\pi r^2 = \frac{22}{7} × 7×7 = 154 cm^2 \)
Now, the length of the wire is bent into a square.
Here perimeter of square= 44cm
Length of each side of the square
= Perimeter/ 4=44/4=11cm
Area of the square = \((Side)^2 = (11)^2 = 121 cm^2 \)
Since, \( 154 cm^2 >121 cm^2 \)
Thus, the circle encloses more area.