Q.10 From a circular card sheet of radius 14 cm, two circles of radius 3.5 cm and a rectangle of length 3 cm and breadth 1 cm are removed, (as shown in the given figure below). Find the area of the remaining sheet. (Take $$\pi = \frac{22}{7}$$ )

Given: Radius of the circular sheet = 14 cm
$$\therefore Area = \pi r^2 =\frac{22}{7} × 14 × 14 cm^2 = 616 cm^2$$
Area of 2 small circles $$= 2 × \pi × r^2$$
$$= 2 × \frac{22}{7} × 3.5 × 3.5 cm^2$$ = 77.0 $$cm^2$$
Area of the rectangle = l × b
=$$3 × 1 cm^2 = 3 cm^2$$
Area of the remaining sheet after removing the 2 circles and 1 rectangle
= $$616 cm^2 – (77 + 3) cm^2$$
= $$616 cm^2 – 80 cm^2 = 536 cm^2$$