Q.10 From a circular card sheet of radius 14 cm, two circles of radius 3.5 cm and a rectangle of length 3 cm and breadth 1 cm are removed, (as shown in the given figure below). Find the area of the remaining sheet. (Take \(\pi = \frac{22}{7} \) )

Given: Radius of the circular sheet = 14 cm
\(\therefore Area = \pi r^2 =\frac{22}{7} × 14 × 14 cm^2 = 616 cm^2 \)
Area of 2 small circles \( = 2 × \pi × r^2 \)
\( = 2 × \frac{22}{7} × 3.5 × 3.5 cm^2 \) = 77.0 \( cm^2 \)
Area of the rectangle = l × b
=\( 3 × 1 cm^2 = 3 cm^2 \)
Area of the remaining sheet after removing the 2 circles and 1 rectangle
= \( 616 cm^2 – (77 + 3) cm^2 \)
= \( 616 cm^2 – 80 cm^2 = 536 cm^2 \)