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Answer :
Given: Radius of the outer circle = 19 m
\(\therefore Circumference of the outer circle = 2\pi r \)
= 2 × 3.14 × 19 = 3.14 × 38 m = 119.32 m
Radius of the inner circle = 19m – 10m = 9m
\(\therefore Circumference = 2 \pi r = 2 × 3.14 × 9
= 56.52 m \)
Here the required circumferences are 56.52 m and 119.32 m.