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Q.7 Through a rectangular field of length 90 m and breadth 60 m, two roads are constructed which are parallel to the sides and cut each other at right angles through the centre of the fields. If the width of each road is 3 m, find
(i) the area covered by the roads.
(ii) the cost of constructing the roads at of the rate of Rs. 110 per\( m^2. \)
Answer :


Length of the road along the length of the field = 90 m Breadth = 3 m
\(\therefore Area of this road = l × b
= 90 m × 3 m =\( 270 m^2 \)
Similarly, the area of the road parallel to the breadth of the field = l × b
= 60 m × 3 m =\( 180 m^2\)
Area of the common portion =\( 3m × 3m = 9m^2\)
(i) Area of the two roads = \(270 m^2 + 180 m^2 – 9 m^2 \) =\( 450 m^2 – 9 m^2 = 441 m^2 \)
(ii) Cost of constructing the roads
= Rs. 110 × 441 = Rs. 48,510