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# Which has more number of atoms, 100 grams of sodium or 100 grams of iron (given, atomic mass of Na = 23u, Fe = 56 u)?

Given, Atomic mass of Na=23u

Atomic mass of Fe= 56u

Now,
23g of Na contains $$= 6.022 × 10^{23}$$ atoms

1g of Na contains = $$6.022 × 10^{23} \over 23$$atoms

100g of Na contains = $$6.022 × 10^{23} \over 23$$ × 100 $$= 2.6182 × 10^{24}$$ atoms

Now, 56g of Fe contains = 6.022 × 1023 atoms

1g of Fe contains = $$6.022 × 10^{23} \over 56$$atoms

100g of Fe contains = $$6.022 × 10^{23} \over 56$$ × 100 $$= 1.075 × 10^{24}$$ atoms

Hence 100g of Na has more atoms.