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Answer :
Given, Atomic mass of Na=23u
Atomic mass of Fe= 56u
Now,
23g of Na contains \( = 6.022 × 10^{23} \) atoms
1g of Na contains = \( 6.022 × 10^{23} \over 23 \)atoms
100g of Na contains = \( 6.022 × 10^{23} \over 23 \) × 100 \( = 2.6182 × 10^{24} \) atoms
Now, 56g of Fe contains = 6.022 × 1023 atoms
1g of Fe contains = \( 6.022 × 10^{23} \over 56 \)atoms
100g of Fe contains = \( 6.022 × 10^{23} \over 56 \) × 100 \( = 1.075 × 10^{24} \) atoms
Hence 100g of Na has more atoms.