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Answer :
(i) \(\frac{(2^5)^2× 7^3}{8^3 × 7} \) = \(\frac{(2^{10}× 7^3}{(2^3)^3 × 7} \)
= \(\frac{(2^{10}× 7^3}{{2^9 × 7} \) = \(2^{10-9}× 7^{3-1}\) = \(2^1× 7^2\) =2× 49 = 98
(ii) \(\frac{25×5^2× t^8}{10^3 ×t^4 } \) = \(\frac{5^2×5^2× t^8}{2^3×5^3×t^4 } \)
= \(\frac{5^4× t^8}{2^3×5^3 ×t^4 } \) = \(\frac{5^{4-3}× t^{8-4}}{2^3} \) = \(\frac{5t^4}{2^3} \)
(iii) \(\frac{3^5×10^5× 25}{5^7 ×6^5 } \)= \(\frac{3^5×2^5×5^5× 5^2}{5^7 ×2^5×3^5 } \)
= \(\frac{3^5×5^7× 2^5}{5^7 ×2^5×3^5} \) = 1