Q.4 (a) What should be added to \(x^2 + xy + y^2\) to obtain \(2x^2 + 3xy? \)
(b) What should be subtracted from 2a + 8b + 10 to get -3a + 7b + 16?


Answer :

(a) \( p + (x^2 + xy + y^2) = 2x^2 + 3xy \)
\(p = (2x^2 + 3xy) – (x^2 + xy + y^2)\)
\(p = 2x^2 + 3xy – x^2 – xy – y^2 \)
\(p = 2x^2 – x^2 + 3xy – xy – y^2\)
\(p = x^2 + 2xy – y^2 \)
(b) 2a + 8b + 10 – m = -3a + 7b + 16
m = (2a + 8b + 10) – (-3a + 7b + 16)
m = 2a + 8b + 10 + 3a – 7b – 16
m = 2a + 3a + 8b – 7b + 10 – 16
m = 5a + b – 6

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