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# Q.4 If a = 2, b = -2, find the value of: $$(i) a^2 + b^2$$ $$(ii) a^2 + ab + b^2$$ $$(iii) a^2 – b^2$$

$$(i) a^2 + b^2$$
$$= (2)^2 + (-2)^2$$
= 4 + 4
= 8
$$(ii) a^2 + ab + b^2$$
$$= 2^2 + (2 × -2) + (-2)^2$$
= 4 + (-4) + (4)
= 4 – 4 + 4
= 4
$$(iii) a^2 – b^2$$
$$= 2^2 – (-2)^2$$ = 4 – (4)
= 4 – 4
= 0