Q.5 When a = 0, b = -1, find the value of the given expressions:
\((i) 2a + 2b \)
\((ii) 2a^2 + b^2 + 1\)
\((iii) 2a^2b + 2ab^2 + ab\)
\((iv) a^2 + ab + 2\)


Answer :

(i) 2a + 2b
= 2(0) + 2(-1)
= 0 – 2 = -2
\((ii) 2a^2 + b^2 + 1\)
\(= 2(0)^2 + (-1)^2 + 1 \)
=0 + 1 + 1 = 2
\((iii) 2a^2b + 2ab^2 + ab\)
\(= 2(0)^2 (-1) + 2(0)(-1)^2 + (0)(-1)\)
=0 + 0 + 0 = 0
\((iv) a^2 + ab + 2\)
\(= (0)^2 + (0)(-1) + 2\)
= 0 + 0 + 2 = 2

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