Premium Online Home Tutors
3 Tutor System
Starting just at 265/hour
Answer :
1 mole of aluminium oxide = 6.022 × 1023 molecules of aluminium oxide
1 mole of aluminium oxide Al2O3
= 2 × Mass of aluminium + 3 × Mass of Oxygen
= (2 × 27) + (3 × 16) = 54 + 48 = 102g
1 mole of aluminium oxide \( = 102g = 6.022 × 10^{23} \) molecules of aluminium oxide
Therefore, 0.051g of aluminium oxide has
\( = \) \( 0.051 × 6.022 × 10^{23} \over 102 \)
\( = 3.011 × 10^{20} \) molecules of aluminium oxide
One molecule of aluminium oxide has 2 aluminium ions, hence number of aluminium ions present in 0.051g of aluminium oxide
\( = 2 ×3.011 × 10^{20} \) ions of aluminium
\( = 6.022 × 10^{20} \) ions of aluminium