(a) 92 __ 389

(b) 8 __ 9484

Answer :

(a) 92 ___ 389

Let, at the missing digit be x

Sum of the digits at odd places = 9 + 3 + 2 = 14

Sum of the digits at even places = 8 + x + 9 = 17

Difference = 17 + x – 14 = x + 3

For the given number to be divisible by 11

x + 3 = 11

x = 11 – 3 = 8

So, the missing digit = 8

Hence, the required number is 928389.

(b) 8 ___ 9484

Let the missing digit be x

Sum of the digits at odd places = 4 + 4 + x = 8 + x

Sum of the digits at even places = 8 + 9 + 8 = 25

? Difference = 25 – (8 + x)

= 25 – 8 – x = 17 – x

For the given number to be divisible by 11

17 – 0 = 11

\(\therefore \)17 – 11 = 6

So, the missing digit = 6

Hence, the required number = 869484.

- NCERT solutions for class 6 maths chapter 1 Knowing Our Numbers
- NCERT solutions for class 6 maths chapter 2 Whole Numbers
- NCERT solutions for class 6 maths chapter 3 Playing with Numbers
- NCERT solutions for class 6 maths chapter 4 Basic Geometrical Ideas
- NCERT solutions for class 6 maths chapter 5 Understanding Elementary Shapes
- NCERT solutions for class 6 maths chapter 6 Integers
- NCERT solutions for class 6 maths chapter 7 Fractions
- NCERT solutions for class 6 maths chapter 8 Decimals
- NCERT solutions for class 6 maths chapter 9 Data Handling
- NCERT solutions for class 6 maths chapter 10 Mensuration
- NCERT solutions for class 6 maths chapter 11 Algebra
- NCERT solutions for class 6 maths chapter 12 Ratio and Proportion
- NCERT solutions for class 6 maths chapter 13 Symmetry
- NCERT solutions for class 6 maths chapter 14 Practical Geometry

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- NCERT solutions for class 6 science chapter 2 Components of Food
- NCERT solutions for class 6 science chapter 3 Fibre to Fabric
- NCERT solutions for class 6 science chapter 4 Sorting Materials into Groups
- NCERT solutions for class 6 science chapter 5 Separation of Substances
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