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Answer :
The greatest 3-digit number = 999
$$
\begin{array}{|l}
\llap{2~~~~} 8, 10, 12 \\ \hline
\llap{2~~~~} 4, 5, 6 \\ \hline
2, 5, 3
\end{array}
$$
LCM = 2× 2× 2 × 5 × 3 = 120
Now we need to find the greatest 3-digit multiple of 120
\(\therefore \) 120 × 8 = 960 and 120 × 9 = 1080
Hence, 960 is the greatest 3-digit number exactly divisible by 8, 10 and 12