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Answer :
Maximum capacity of the required measure is equal to the HCF of 403, 434 and 465.
$$
\begin{array}{|l}
\llap{13~~~~} 403 \\ \hline
\llap{31~~~~} 31 \\ \hline
1
\end{array}
$$
$$
\begin{array}{|l}
\llap{2~~~~} 434 \\ \hline
\llap{7~~~~} 217 \\ \hline
\llap{31~~~~} 31 \\ \hline
1
\end{array}
$$
$$
\begin{array}{|l}
\llap{3~~~~} 465 \\ \hline
\llap{5~~~~} 155 \\ \hline
\llap{31~~~~} 31 \\ \hline
1
\end{array}
$$
403=13× 31
434 = 2 × 7 × 31
465 = 3 × 5 × 31
HCF = 31
Hence, the maximum capacity of the required container = 31 litres.