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Answer :

$$
\begin{array}{|l}
\llap{2~~~~} 6, 15, 18 \\ \hline
\llap{3~~~~} 3, 15, 9 \\ \hline
1, 5, 3
\end{array}
$$
LCM = 2×3×5×3 = 90

Here, 90 is the least number exactly divisible by 6, 15 and 18.

To get a remainder 5, the least number will be 90 + 5 = 95.

Hence, 95 is the required number.

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- NCERT solutions for class 6 maths chapter 1 Knowing Our Numbers
- NCERT solutions for class 6 maths chapter 2 Whole Numbers
- NCERT solutions for class 6 maths chapter 3 Playing with Numbers
- NCERT solutions for class 6 maths chapter 4 Basic Geometrical Ideas
- NCERT solutions for class 6 maths chapter 5 Understanding Elementary Shapes
- NCERT solutions for class 6 maths chapter 6 Integers
- NCERT solutions for class 6 maths chapter 7 Fractions
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- NCERT solutions for class 6 maths chapter 11 Algebra
- NCERT solutions for class 6 maths chapter 12 Ratio and Proportion
- NCERT solutions for class 6 maths chapter 13 Symmetry
- NCERT solutions for class 6 maths chapter 14 Practical Geometry

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- NCERT solutions for class 6 science chapter 2 Components of Food
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- NCERT solutions for class 6 science chapter 4 Sorting Materials into Groups
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