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Answer :

we have AG = 7 unit – 1 unit = 6 unit

AD = 4 unit – 1 unit = 3 unit

and DG = 7 unit – 4 unit = 3 unit

\(\therefore \)AG = AD + DG.

Hence, D is the mid point of AG.

- Q.1 What is the disadvantage in comparing line segments by mere observation?
- Q.2 Why is it better to use a divider than a ruler, while measuring the length of a line segment?
- Q.3 Draw any line segment, say \(\overline {AB} \). Take any point C lying in between A and B. Measure the lengths of AB, BC and AC. Is AB = AC + CB? [Note: If A, B, C are any three points on a line such AC + CB = AB, then we can be sure that C lies between A and B]
- Q.4 If A, B, C are three points on a line such that AB = 5 cm, BC = 3 cm and AC = 8 cm, which one of them lies between the other two?
- Q.6 If B is the mid point of AC and C is the mid point of BD , where A, B, C, D lie on a straight line, say why AB = CD?
- Q.7 Draw five triangles and measure their sides. Check in each case, if the sum of the lengths of any two sides is always less than the third side.

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