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# Q.7 Draw five triangles and measure their sides. Check in each case, if the sum of the lengths of any two sides is always less than the third side.

(I) In first figure,
It is an equalatral triangle
Sum of two side = 5 + 5 = 10
10 > 5 Hence, the sum of any two sides of a triangle is greater than the third side.
(II) In second figure ,
Sum of two side = 5 + 5 = 10 , 5 + 3 = 8 , 5 + 3 = 8
$$\therefore$$ 10 > 3, 8 > 5 , 8 > 5
Hence, the sum of any two sides of a triangle is greater than the third side.
(III) In third figure,
Sum of two side = 6 + 10 = 16 , 8 + 10 = 18 , 6 + 8 = 14
$$\therefore$$ 16 > 8, 18 > 6, 14 > 10
Hence, the sum of any two sides of a triangle is greater than the third side.
(IV) In forth figure,
Sum of two side = 6 + 7 = 13 , 7 + 6 = 13 , 6 + 6 = 12
$$\therefore$$ 13 > 6, 13 > 6, 12 > 7
Hence, the sum of any two sides of a triangle is greater than the third side.
(IV) In fifth figure,
Sum of two side = 12 + 5 = 17 , 13 + 5 = 18 , 12 + 13 = 25
$$\therefore$$ 17 > 13, 18 > 12, 25 > 5
Hence, the sum of any two sides of a triangle is greater than the third side.
Therefore we conclude that the sum of any two sides of a triangle is always greater than the third side.