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# Q.7 Draw five triangles and measure their sides. Check in each case, if the sum of the lengths of any two sides is always less than the third side.

Answer :

(I) In first figure,
It is an equalatral triangle
Sum of two side = 5 + 5 = 10
10 > 5 Hence, the sum of any two sides of a triangle is greater than the third side.
(II) In second figure ,
Sum of two side = 5 + 5 = 10 , 5 + 3 = 8 , 5 + 3 = 8
$$\therefore$$ 10 > 3, 8 > 5 , 8 > 5
Hence, the sum of any two sides of a triangle is greater than the third side.
(III) In third figure,
Sum of two side = 6 + 10 = 16 , 8 + 10 = 18 , 6 + 8 = 14
$$\therefore$$ 16 > 8, 18 > 6, 14 > 10
Hence, the sum of any two sides of a triangle is greater than the third side.
(IV) In forth figure,
Sum of two side = 6 + 7 = 13 , 7 + 6 = 13 , 6 + 6 = 12
$$\therefore$$ 13 > 6, 13 > 6, 12 > 7
Hence, the sum of any two sides of a triangle is greater than the third side.
(IV) In fifth figure,
Sum of two side = 12 + 5 = 17 , 13 + 5 = 18 , 12 + 13 = 25
$$\therefore$$ 17 > 13, 18 > 12, 25 > 5
Hence, the sum of any two sides of a triangle is greater than the third side.
Therefore we conclude that the sum of any two sides of a triangle is always greater than the third side.