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Answer :
(a) \(\frac{(7 × 4 + 3)}{4} = \frac{31}{4} \)
\(\therefore \) The improper form is \(\frac{31}{4} \)
(b) \(\frac{(5 × 7 + 6)}{7} = \frac{41}{7} \)
\(\therefore \) The improper form is \(\frac{41}{7} \)
(c) \(\frac{(2 × 6 + 5)}{6} = \frac{17}{6} \)
\(\therefore \) The improper form is \(\frac{17}{6} \)
(d) \(\frac{(10 × 5 + 3)}{5} = \frac{53}{5} \)
\(\therefore \) The improper form is \(\frac{53}{5} \)
(e) \(\frac{(9 × 7 + 3)}{7} = \frac{66}{7} \)
\(\therefore \) The improper form is \(\frac{66}{7} \)
(f) \(\frac{(8 × 9 + 4)}{9} = \frac{76}{9} \)
\(\therefore \) The improper form is \(\frac{76}{9} \)