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# Q.2 Solve: (a) $$\frac{1}{18} + \frac{1}{18}$$ (b) $$\frac{8}{15} + \frac{3}{15}$$ (c) $$\frac{7}{7} - \frac{5}{7}$$ (d) $$\frac{1}{22} + \frac{21}{22}$$ (e) $$\frac{12}{15} - \frac{7}{15}$$ (f) $$\frac{5}{8} + \frac{3}{8}$$ (g) 1 – $$\frac{2}{3}$$ (1 = $$\frac{3}{3}$$ ) (h) $$\frac{1}{4} + \frac{0}{4}$$ (i) 3 - \frac{12}{5} \)

(a) $$\frac{1}{18} + \frac{1}{18}$$ = $$\frac{2}{18} = \frac{1}{9}$$
(b) $$\frac{8}{15} + \frac{3}{15}$$ = $$\frac{11}{15}$$
(c) $$\frac{7}{7} - \frac{5}{7}$$ = $$\frac{2}{7}$$
(d) $$\frac{1}{22} + \frac{21}{22}$$ = $$\frac{22}{22}$$ = 1
(e) $$\frac{12}{15} - \frac{7}{15}$$ = $$\frac{5}{15}$$ = $$\frac{1}{5}$$
(f) $$\frac{5}{8} + \frac{3}{8}$$ = $$\frac{8}{8}$$ = 1
(g) 1 – $$\frac{2}{3}$$ (1 = $$\frac{3}{3}$$ )
= $$\frac{3}{3}$$ - $$\frac{2}{3}$$ = $$\frac{1}{3}$$
(h) $$\frac{1}{4} + \frac{0}{4}$$ = $$\frac{1}{4}$$
(i) 3 - \frac{12}{5} \) = $$\frac{15-12}{5}$$ = $$\frac{3}{5}$$