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Answer :
Time taken by Jaidev to walk across the school ground =\(2\frac{1}{5} \) = \(\frac{11}{5} \) minutes
Time taken by Rahul to walk across the school ground =
\(\frac{7}{4} \) minutes
\(\frac{11}{5} \) and \(\frac{7}{4} \)
By cross multiplication
11×4 and 5×7
44 > 35
\(\frac{11}{5} \) > \(\frac{7}{4} \)
\(\therefore \) Rahul takes less time than Jaidev to walk across the school ground
Difference = \(\frac{11}{5} \) - \(\frac{7}{4} \)
= \(\frac{11×4}{5×4} \) - \(\frac{7×5}{4×5} \)
= \(\frac{44}{20} \) - \(\frac{35}{20} \)
= \(\frac{9}{20} \)