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Answer :
The distances of potatoes from the bucket are 5, 8, 11, 14…, which is in the form of AP.
Given, the distance run by the competitor for collecting these potatoes are two times of the distance at which the potatoes have been kept.
Therefore, distances to be run w.r.t distances of potatoes, could be written as;
10, 16, 22, 28, 34,……….
Hence, the first term, a = 10 and d = 16 - 10 = 6
S10 =?
By the formula of sum of n terms, we know,
\(S_{10} = {{12} \over {2}} [2(20)+(n -1)(-1)]\)
= 5[20+54]
= 5(74)
= 370
Therefore, the competitor will run a total distance of 370 m.