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# Express the following linear equations in the form ax + by + c = 0 and indicate the values of a, b and c in each case. i) $$2x + 3y = 9\overline{.35}$$ ii)$$x - \frac{y}{5} - 10 = 0$$ iii) -2x + 3y = 6 iv) x = 3y v) 2x = -5y vi) 3x + 2 = 0 vii) y - 2 = 0 viii)5 = 2x

Answer :

i)$$2x + 3y = 9\overline{.35}$$
Rearranging the terms we get,
$$2x + 3y - 9\overline{.35} = 0$$
On comparing with ax + by + c = 0, then the values of a = 2, b = 3 and c = -$$9\overline{.35}$$

ii)$$x - \frac{y}{5} - 10 = 0$$
Rearranging the terms we get,
$$x - \frac{y}{5} - 10 = 0$$
On comparing with ax + by + c = 0, then the values of a = 1, b = $$\frac{-1}{5}$$ and c = -10

iii)-2x + 3y = 6
Rearranging the terms we get,
-2x + 3y - 6 = 0
On comparing with ax + by + c = 0, then the values of a = -2, b = 3 and c = -6

iv)x = 3y
Rearranging the terms we get,
x - 3y + 0= 0
On comparing with ax + by + c = 0, then the values of a = 1, b = -3 and c = 0

v)2x = -5y
Rearranging the terms we get,
2x + 5y + 0 = 0
On comparing with ax + by + c = 0, then the values of a = 2, b = 5 and c = 0

vi)3x + 2 = 0
Rearranging the terms we get,
3x + (0)y + 2 = 0
On comparing with ax + by + c = 0, then the values of a = 3, b = 0 and c = 2

vii)y - 2 = 0
Rearranging the terms we get,
(0)x + y - 2 = 0
On comparing with ax + by + c = 0, then the values of a = 0, b = 1 and c = -2

viii)5 = 2x
Rearranging the terms we get,
2x + (0)y - 5 = 0
On comparing with ax + by + c = 0, then the values of a = 2, b = 0 and c = -5