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Write four solutions for each of the following equations : i) 2x + y = 7 ii) $$\pi$$x + y = 9 iii) x = 4y

i)By inspection, x = 2 and y = 3 is a solution because for these values of x and y,

we get,2(2) + 3 = 4 + 3 = 7

Now, if we put x = 0, then the equation reduces to an unique solution of y = 7.

So, one solution of 2x + y = 7 is (0, 7).

Similarly, if we put y = 0, then the equation reduces to an unique solution of x = $$\frac{7}{2}$$.

So, another solution of 2x + y = 7 will be ($$\frac{7}{2}$$ , 0).

Finally, let us put x = 1, then,

we get, 2(1) + y = 7
=> 2 + y = 7
=> y = 5

Hence, (1, 5) is also a solution of given equation.

Therefore, four of the infinitely many solutions of the equation 2x + y = 7 are :
(2, 3) , (0, 7) , ($$\frac{7}{2}$$ , 0) and (1, 5).

ii)By inspection, x = $$\frac{1}{\pi }$$ and y = 8 is a solution because for these values of x and y,

we get,$$\pi (\frac{1}{\pi}$$) + 8 = 1 + 8 = 9

Now, if we put x = 0, then the equation reduces to an unique solution of y = 9.

So, one solution of $$\pi$$x + y = 9 is (0, 9)).

Similarly, if we put y = 0, then the equation reduces to an unique solution of x = $$\frac{9}{\pi }$$.

So, another solution of 2x + y = 7 will be ($$\frac{9}{\pi }$$, 0).

Finally, let us put x = 1, then,

we get, $$\pi$$(1) + y = 9
=> $$\pi$$ + y = 9
=> y = 9 - $$\pi$$

Hence, (1, 9 - $$\pi$$) is also a solution of given equation.

Therefore, four of the infinitely many solutions of the equation 2x + y = 7 are :
($$\frac{1}{ \pi }$$, 8) , (0, 9) , ($$\frac{9}{\pi }$$, 0) and (1, 9 - $$\pi$$).

iii)By inspection, x = 0 and y = 0 is a solution because for these values of x and y,

we get,0 = 4(0) => 0 = 0
Now, if we put x = 4, then the equation reduces to solution of y = 1.

So, one solution of x = 4y is (4, 1).

Similarly, if we put y = -1, then the equation reduces to solution of x = -4.

So, another solution of x = 4y will be (-4, -1).

Finally, let us put y = $$\frac{1}{2}$$ , then,
we get, x = 4($$\frac{1}{2}$$)
=> x = 2

Hence, (2, $$\frac{1}{2}$$ ) is also a solution of given equation.

Therefore, four of the infinitely many solutions of the equation x = 4y are :
(0, 0) , (4, 1) , (-4, -1) and (2, $$\frac{1}{2}$$ ).