Answer :

(i) Draw a line 'l 'Mark a point A on this line.

(ii) Place the compasses pointer on zero mark of the ruler. Open it to place the pencil pointup to 5.6 cm mark.

(iii) Without changing the opening of the compasses. Place the pointer on A and cut an arc' l ' at B. AB is the required line segment of length 5.6 cm.

- Q.1 Draw a line segment of length 7.3 cm using a ruler.
- Q.3 Construct \(\overline{AB} \) of length 7.8 cm. From this, cut off \(\overline{AC} \) of length 4.7 cm. Measure \(\overline{BC} .\)
- Q.4 Given \(\overline{AB} \) of length 3.9 cm. Construct (\overline{PQ} \) such that the length of (\overline{PQ} \) is twice that of (\overline{AB} \) . Verify by measurement. (Hint : Construct \(\overline{PX} \) such that the length of \(\overline{PX} \) = length of \(\overline{AB} \) then cut off \(\overline{XQ} \) such that \(\overline{XQ} \) also has the length of \(\overline{AB} \) .
- Q.5 Given \(\overline{AB} \) of length 7.3 cm and \(\overline{CD} \) of length 3.4 cm, construct a line segment \(\overline{XY} \) such that the length of XY is equal to the difference between the length of \(\overline{AB} \) and \(\overline{CD} \) . Verify the measurement.

- NCERT solutions for class 6 maths chapter 1 Knowing Our Numbers
- NCERT solutions for class 6 maths chapter 2 Whole Numbers
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- NCERT solutions for class 6 maths chapter 12 Ratio and Proportion
- NCERT solutions for class 6 maths chapter 13 Symmetry
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