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The taxi fare in a city is as follows:
For the first kilometer, the fare is Rs. 8 and for the subsequent distance it is Rs. 5 per km.
Taking the distance covered as x km and the total fare as Rs. y, write a linear equation for this information and draw its graph.
Answer :
Distance covered = x km = 1 + (x – 1) km
The fare for the first kilometer is Rs. 8.
Fare for next (x - 1)km
= (x - 1) × 5
= 5(x - 1).
According to question, Total fare = y.
\(\therefore \) 8 + 5(x - 1) = y
\(\Rightarrow \) 8 + 5x - 5 = y
So, the equation becomes 5x - y + 3 = 0
| x | 0 | 1 |
|---|---|---|
| y | 3 | 8 |
| (x, y) | (0, 3) | (1, 8) |
Now, plot the points (0, 3) and (1, 8) on a graph paper and joining them, to form a line .
