# Find the ratio in which the line segment joining the points (-3, 10) and (6, – 8) is divided by (-1, 6).

Let the required ratio be k : 1
By section formula ,

$$x = \frac{m1x2 + m2x1}{m1+m2}$$
$$\Rightarrow -1 = \frac{k×6 + 1× -3 )}{k+1}$$
$$\Rightarrow -k-1 = 6k -3$$
$$\Rightarrow 7k = 2$$
$$\Rightarrow k = \frac{2}{7}$$

The required ratio = k : 1
= $$\frac{2}{7}$$ : 1 = $$\frac{2}{7} ×7 : 1×7$$ = 2 : 7