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Q.3 Construct a triangle with sides 5 cm, 6 cm and 7 cm and then another triangle whose sides are \(\frac{7}{5} \) of the corresponding sides of the first triangle

Answer :

Step of construction: 1. Draw a triangle which has AB = 5 cm, BC = 6cm , and CA = 7 cm
2. Draw an acute angle CBX below BC at point B .
3. Mark the ray BX as B1, B2 B3,B4 ....B7 such that BB1= B1B2................B6=B7
4.join B5 to C
5. Draw B7 C' || to B5C , where C' is extended line BC.
6. Draw A'C'|| AC where A' is a point on extended line BA.
7. A'BC' is required triangle

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