# ABC is a triangle. Locate a point in the interior of $$\triangle$$ ABC which is equidistant from all the vertices of $$\triangle$$ABC.

In $$\triangle$$ABC, we can find the circumcentre by drawing the perpendicular bisectors of sides AB, BC, and CA of this triangle. O is the point where these bisectors are meeting together. Therefore, O is the point which is equidistant from all the vertices of $$\triangle$$ABC.