In figure, ABCD, DCFE and ABFE are parallelograms. Show that ar(ADE) = ar(BCF).


Answer :

Since, ABCD is a parallelogram [Given]
\(\therefore \)Its opposite sides are parallel and equal.
\(\Rightarrow \) AD = BC …(1)

Now, \(\triangle \)ADE and \(\triangle \)BCF are on equal bases AD = BC [from (1)] and between the same parallels AB and EF.

So, ar(\(\triangle \)ADE) = ar(\(\triangle \)BCF).

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